5x^2-5x+4=0

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Solution for 5x^2-5x+4=0 equation:


Simplifying
5x2 + -5x + 4 = 0

Reorder the terms:
4 + -5x + 5x2 = 0

Solving
4 + -5x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.8 + -1x + x2 = 0

Move the constant term to the right:

Add '-0.8' to each side of the equation.
0.8 + -1x + -0.8 + x2 = 0 + -0.8

Reorder the terms:
0.8 + -0.8 + -1x + x2 = 0 + -0.8

Combine like terms: 0.8 + -0.8 = 0.0
0.0 + -1x + x2 = 0 + -0.8
-1x + x2 = 0 + -0.8

Combine like terms: 0 + -0.8 = -0.8
-1x + x2 = -0.8

The x term is -1x.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1x + 0.25 + x2 = -0.8 + 0.25

Reorder the terms:
0.25 + -1x + x2 = -0.8 + 0.25

Combine like terms: -0.8 + 0.25 = -0.55
0.25 + -1x + x2 = -0.55

Factor a perfect square on the left side:
(x + -0.5)(x + -0.5) = -0.55

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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